What radius of a circle is required to inscribe an equilateral triangle with an area of 270.633 cm2 and an altitude of 21.65 cm? (round to nearest tenth)
Area of an equilateral triangle=(sqrt(3)/4)x^2=270.633 x^2=270.633/[sqrt(3)/4] x^2=625 x=25 thus the length of equilateral is 25 cm thus the radius will be given by: r=25/sqrt(3)=14.43 cm
