Answer:
Moles of N = 3.45
Explanation:
Given:
Mass of N2O = 76.0 g
To determine:
Moles of N present in the given mass of N2O
Explanation:
Based on the formula stoichiometry:
1 mole of N2O contains 2 moles of N
Now, 1 mole of N2O = 44.0 g (i.e. the molar mass of N2O)
44.0 g of N2O contains 2 moles of N
Therefore, moles of N in 76.0 g of N2O would be:
= [tex]= \frac{76.0 g \ N2O *2\ moles\ N}{44.0g\ N2O} =3.45\ moles[/tex]
