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Two perfumes are released at the same time. If one is standing 7.5 m from the point of release. Perfume A (molar mass 275 g/mol) and perfume B (molar mass 205 g/mol) at the same temperature. I. Which perfume will the person smell first and why?

Respuesta :

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According to Graham's Law of Diffusion," Diffusion of Gas is inversely proportional to square root of its Molecular Mass or Density".

                          rᵇ/rᵃ  =  [tex] \sqrt{da/db} [/tex]
Or,
                          rᵇ/rᵃ  =  [tex] \sqrt{Ma/Mb} [/tex]     ----- (1)
As, 
                          Ma  =  275 g/mol

                          Mb  =  205 g/mol

Putting Values in eq.1,

                          rᵇ/rᵃ  =  [tex] \sqrt{275/205} [/tex]

                          rᵇ/rᵃ  =  1.15

Result:
          Perfume B will diffuse 1.15 times faster than Perfume A. Hence, Perfume B will be first smelled by the person.

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