a. The frequency of the dominant allele: ___0.4______
b. The frequency of the recessive allele: ____0.6_____
c. The percentage of mice that are homozygous dominant: __16%_______
d. The percentage of mice that are heterozygous: _48%________
e. The percentage of mice that are homozygous recessive: __36%_______
Let us assign the dominant allele (that of brown hair) letter R while
We assign the recessive allele (that of white hair) letter r
We then note down the Hardy-Weinburg equation p2 + 2pq + q2 = 1
Brown fur population (p2 + 2pq) = 64% = 0.64
White fur population (q2) = 36% = 0.36
Then we also remember that the frequencies of both allele add up to 1 (p + q = 1);
Therefore q = ü.36 = 0.6
P = 1 – q = 1 – 0.6 = 0.4
The heterozygous population will be 2*0.6*0.4 = 0.48 = 48%
Homozygous domain population will therefore be (64% - 48%) = 16%
