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A sample of oxygen gas was collected via water displacement. since the oxygen was collected via water displacement, the sample is saturated with water vapor. if the total pressure of the mixture at 26.4 °c is 817 torr, what is the partial pressure of oxygen

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Missing question:  The vapor pressure of water at 26.4 °C is 25.81 mm Hg.
p(total) = p(H₂O) + p(O₂).
p(total) = 817 torr;  total pressure of the mixture.
p(H₂O) = 25.81 torr, partial pressure of water.
p(O₂) = 817 torr - 25.81.
p(O₂) = 791.19 torr; partial pressure of oxygen.

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