Respuesta :

[tex]\tan(\theta) = \dfrac{\text{opp}}{\text{adj}} [/tex]

[tex]\tan(x) = \dfrac{\text{19}}{\text{11}} [/tex]

[tex]x = \tan^{-1} \bigg(\dfrac{\text{19}}{\text{11}} \bigg)[/tex]

[tex]x = 60 \textdegree \text{ (nearest whole number) }[/tex]

Answer: Option B
x = arctan(base /  height)

x = arctan(19/11)

x = 59.93

x = 60