The following balanced equation shows the formation of ammonia. N2 + 3H2 mc021-1.jpg 2NH3 How many moles of nitrogen are needed to completely convert 6.34 mol of hydrogen? 1.02 mol 2.11 mol 12.68 mol 19.02 mol

Respuesta :

Since the answer is in moles and hydrogen gas is also in mols, there's no need to calculate the molar mass of each reactant.

To solve this question, look to the coefficients of the balanced equation.

Notice how there is a 1:3 ratio between Nitrogen gas & hydrogen gas. This becomes your straight-forward stoichiometry problem.

You have to react all the H2 gas, so start with that:

[tex]6.34mol \times \frac{1mol}{3mol} = 2.11mol \: nitrogen \: gas[/tex]
Coefficients are important in balanced equations because they let us know the ratio between reactants and such. For every mole of N2 gas, there's 3 moles of H2 gas. That is what gives us that answer.

Hope that helps!

For completely converting 6.34 moles of hydrogen to ammonia, 2.11 moles of Nitrogen is required.

The chemical reaction for the formation of ammonia by nitrogen and hydrogen reaction has been as follows:

[tex]\rm N_2\;+\;3\;H_2\;\rightarrow\;2\;NH_3[/tex]

For the formation of 2 moles of ammonia, 3 moles of hydrogen, and 1 mole of nitrogen s required.

The utilization of 3 moles of hydrogen requires 1 mole of Nitrogen.

So, the utilization of 6.34 moles of hydrogen requires:

3 moles Hydrogen = 1 -mole Nitrogen

6.34 moles hydrogen = [tex]\rm \dfrac{1}{3}\;\times\;6.34[/tex] moles of Nitrogen

6.34 moles of hydrogen requires = 2.11 moles of Nitrogen.

For completely converting 6.34 moles of hydrogen to ammonia, 2.11 moles of Nitrogen is required.

For more information about the ammonia formation, refer to the link:

https://brainly.com/question/20986532