The table of values represents a polynomial function ​f(x).

How much greater is the average rate of change over the interval [7, 9] than the interval ​ [4, 6] ​ ?

The table of values represents a polynomial function fx How much greater is the average rate of change over the interval 7 9 than the interval 4 6 class=

Respuesta :

average rate = (f(final)-f(initial))/(x(final)-x(initial))
the interval [7, 9] 
av. rate =(3878-1852)/(9-7)=1013
the  interval ​ [4, 6] 
av. rate =(1178-358)/(6-4)=410
1013-410=603 greater the average rate of change over the interval [7, 9] than the interval ​ [4, 6]

The average rate of change over the interval [7, 9] is 2.37 times larger than  the average rate of change over the interval [4, 6]

How to get the average rate of change?

For a function f(x), the average rate of change on an interval [a, b] is given by:

[tex]a = \frac{f(b) - f(a)}{b - a}[/tex]

So, the average rate of change on the interval [7, 9] is:

[tex]a_{[7,9]} = \frac{3878 - 1852}{9 - 7} = 1013[/tex]

And on the interval [4, 6], it is:

[tex]a_{[4,6]} = \frac{1178 - 358}{6 - 4} = 410[/tex]

To see how much greater is the average rate of change over the interval [7, 9] than the interval ​ [4, 6], we take the quotient between these two values.

1013/410 = 2.37

The average rate of change over the interval [7, 9] is 2.37 times larger than  the average rate of change over the interval [4, 6]

If you want to learn more about the average rate of change, you can read:

https://brainly.com/question/8728504