Answer:
$2000
Step-by-step explanation:
6,000 dollars is invested in two different accounts earning 3% and 5% interest.
Let x be the amount invested in account earning 3% interest
So, 6000-x is the amount invested in account earning 5% interest
[tex]S.I. =\frac{P\times R\times T}{100}[/tex]
So, Simple interest for account earning 3% interest
[tex]S.I. =\frac{x \times 3 \times 1}{100}[/tex]
[tex]S.I. =0.03x[/tex]
Simple interest for account earning 5% interest
[tex]S.I. =\frac{(6000-x) \times 5 \times 1}{100}[/tex]
[tex]S.I. =0.05(6000-x)[/tex]
[tex]S.I. =300-0.05x[/tex]
Since we are given that the two accounts earned $220 in interest
So, [tex]0.03x+300-0.05x=220[/tex]
[tex]−0.02x+300=220[/tex]
[tex]80=0.02x[/tex]
[tex]\frac{80}{0.02}=x[/tex]
[tex]4000=x[/tex]
So, 4000 was invested at 3%
(6000-x)=6000-4000=2000 was invested at 5%
Hence 2000 was invested at 5%
