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If the equation of a circle is (x - 2)2 + (y - 6)2 = 4, it passes through point ______. (-4, 6) (4, 6) (2, 6) (2, -6)

Respuesta :

Riia

The given equation of the circle is

[tex] (x - 2)^2 + (y - 6)^2 = 4 [/tex]

Let's check the point (4,6) by substituting it in the given equation of circle

[tex] (4-2)^2 + (6-6)^2 = 2^2 + 0^2 = 4 [/tex]

Which is equal to the right side.

So the correct option is (4,6) that is the second option .

Jacobswan

Answer:

The correct answer (4, 6)

Step-by-step explanation:

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