Atomic Mass of Magnesium = 24.30 amu
As we know, 1 mole of Mg weights exactly 24.30 amu.
Also,
1 mole of Mg contains 6.022 × 10²³ Atoms.
So, If,
24.30 amu Mg contains = 6.022 × 10²³ Mg Atoms
Then,
24.31 amu of Mg will contain = X Mg Atoms,
Solving for X,
X = (24.31 amu × 6.022 × 10²³ Atoms) ÷ 24.30
X = 6.022 × 10²³ Mg Atoms
Result:
24.31 amu of Mg equals 6.022 × 10²³ Mg Atoms.
