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Rate of change help? Which expression below gives the average rate of change of k on -3 ≤ x ≤ 5 ?

a.) 5 + 3 / k(5) - k(-3)

b.) k(5) - k(-3) / 5 + 3

c.) k(-3) + k(5) / 5 - (-3)

d.) 5 - (-3) / k(-3) + k(5)

Respuesta :

popalabdulqayou
B is right because of slope = (y2-y1)/(x2-x1)
so k(5)-k(-3)/5+3 is the same to given slope equation.

The average rate of change of 'k' on -3 ≤ x ≤ 5 is [tex]\frac{k(5)-k(-3)}{5+3}\\[/tex].

What is the average rate of change of a function in an interval?

For a function k(x), the average rate of change in the interval [tex](x_{1}, x_{2})[/tex] is:

[tex]\frac{k(x_{2})-k(x_{1})}{x_{2}-x_{1}}[/tex]

The given inequality is:

-3 ≤ x ≤ 5

Here, [tex]x_{1} = - 3, x_{2} = 5[/tex]

Therefore, the average rate of change of k(x) in the interval (-3, 5) is

[tex]\frac{k(5)-k(-3)}{5-(-3)}\\= \frac{k(5)-k(-3)}{5+3}\\[/tex]

Learn more about the inequality here: https://brainly.com/question/11749512

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