Answer: The correct option is
(A) ±4
Step-by-step explanation: We are given to solve the following quadratic equation using the method of square roots :
[tex]-x^2+16=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)[/tex]
In square root method, we should take x² term on one side and the constant the on other side of the equation Then, we should take the square roots.
From equation (i), we have
[tex]-x^2+16=0\\\\\Rightarrow x^2=16\\\\\Rightarrow x=\pm\sqrt{16}~~~~~~~~~~~~~~~~~~~~~~~~[\textup{taking square root on both sides}]\\\\\Rightarrow x=\pm4.[/tex]
Thus, the required solution of the given equation is x = ±4.
Option (A) is CORRECT.
