Respuesta :

check the picture below.

[tex]\bf \stackrel{\textit{area of the semicircle}}{\frac{\pi r^2}{2}}~~~~+~~~~\stackrel{\textit{area of the triangle}}{\frac{1}{2}bh} \\\\\\ \stackrel{\textit{area of the semicircle}}{\frac{\pi 4^2}{2}}~~~~+~~~~\stackrel{\textit{area of the triangle}}{\frac{1}{2}(12)(8)} \\\\\\ 8\pi +48\qquad \approx\qquad 73.1327412287[/tex]
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