Reaction of Ammonium Perchlorate and Aluminium is as follow,
3 Al + 3 NH₄ClO₄ → Al₂O₃ + AlCl₃ + 3 NO + 6 H₂O
According to Equation,
0.352 Kg (3 moles) of NH₄ClO₄ required = 0.081 Kg of Al for reaction
So,
56 Kg of NH₄ClO₄ will require = X Kg of Al
Solving for X,
X = (56 Kg × 0.081 Kg) ÷ 0.352 Kg
X = 12.88 Kg of Aluminium
Or,
X = 12800 g of Aluminium
Result:
12800 g of Aluminium is required to react with 56 Kg of Ammonium Perchlorate.
