Answer:
[tex]3a(16a^2-25)[/tex]
[tex]3a(4a-5)(4a+5)[/tex]
Step-by-step explanation:
The equation [tex]48a^3-75a[/tex] is factorable using GCF and difference of squares.
First, we factor 3a from each term.
[tex]3a(16a^2-25)[/tex]
The term in the parenthesis [tex]{16a^2-25)[/tex] has the form [tex]a^2-b^2 = (a-b)(a+b)[/tex] which factors into two terms where a and b are the squares root of their respective terms.
[tex]3a(16a^2-25)\\3a(4a-5)(4a+5)[/tex]
