The famous black planet, haunch, has a radius of 106 m, a gravitational acceleration at the surface of 4 m/s2 , and the tangential speed of any point on its equator is 103 m/s. a famous haunch ant has a mass of 40 kg and is standing on a spring scale at the equator. what is the reading of the spring scale?

Gravity on the surface = 4 m/s^2
Now, the acceleration due to centripetal motion, a = v^2/R

Where,
v= 10^3 m/s, R = 10^6 m
Then,
a = (10^3)^2/(10^6) = 1 m^2/s

The net gravitational acceleration = 4-1 = 3 m/s^2

The reading on the spring scale = ma = 40*3 = 120 N

Answer Link

hamzaahmeds hamzaahmeds · Answer 2 · 2021-11-09T12:01:55+01:00

This question involves the concepts of centripetal acceleration and gravitational acceleration.

The reading of the spring scale is "120 N".

The apparent weight that is the reading of the spring scale is given by the following formula:

[tex]W=m(net\ acceleration)\\W=m(g-a)[/tex]

where,

m = mass of ant = 40 kg

g = gravitational acceleration = 4 m/s²

a = centripetal acceleration = [tex]\frac{v^2}{r}=\frac{(10^3\ m/s)^2}{10^6\ m} = 1\ m/s^2[/tex]

Therefore,

[tex]W = (40\ kg)(4\ m/s^2-1\ m/s^2)\\[/tex]

W = 120 N

Learn more about the centripetal acceleration here:

brainly.com/question/14465119?referrer=searchResults

The attached picture explains the concept of centripetal acceleration.