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The voltaic cell made up of cobalt, copper, and their m2+ ions, has e°cell = 0.62 v. if e° of the cathode half-cell is 0.34 v, what is e° of the anode half-cell? cu2+(aq) + co(s) → cu(s) + co2+(aq)

Respuesta :

Since that E°cell =E°cathode - E°anode then 
0.62V = 0.34 - E°anode
Therefore E° anode is = -0.28V
pstnonsonjoku

Answer:

-0.28V

Explanation:

E°cell= E°cathode- E°anode

E°cell=0.62V

E°cathode= 0.34V

E°anode= E°cathode- E°cell

E°anode= 0.34-0.62

E°anode= -0.28V