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kenmyna
The volume that  would  be  occupied   by  0.25  moles   sample  of  H2  is    calculated  using  ideal  gas  equation  formula

that is  PV  =nRT

P(pressure)=  1.7  atm
V( volume)? 
n(number of moles)= 0.250  moles
R(gas  constant)=0.0821  l.atm/mol.K
T (temperature in  kelvin)=35+273  =  308k

by  making V the  subject  of the  formula V=nRT/P

=(0.250  moles  x  0.0821  L.atm/k.mol  x 308 k)/( 1.70 atm)  = 3.7  L  of  H2  gas

A 0.250 mole sample of Hydrogen gas occupy 3.7 L volume , if it had a which has a pressure of 1.70 atm, and a temperature of 35 °c

Gas volume formula,

[tex]\rm \bold { V=\frac{nRT}{P} }[/tex]

Where,

n - number of moles = 0.250  moles

R - gas  constant =0.0821  L.atm/mol.K

T - temperature in  kelvin = 35+273  =  308k

P - pressure =  1.7  atm

Put the value in the formula we get

V = 3.7  L

Hence, we can conclude that  a 0.250 mole sample of Hydrogen gas occupy 3.7 L volume , if it had a which has a pressure of 1.70 atm, and a temperature of 35 °c

To know more about gas law, refer to the link:

https://brainly.com/question/12669509?referrer=searchResults

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