a. what is the frequency of the dominant allele in this population?
Let say N is dominant allele and n is the recessive allele. The disease is autosomal recessive so the patient should be homozygous recessive(nn).
If the frequency of nn is 1/750, then the frequency of n would be: √(1/750)= 0.0365 = 3.65%
b. assuming mating occurs at random in this population, what is the probability that a couple are both carriers of this disorder?
If the frequency of n is 3.65%, the frequency of N would be:
1=n+N
1=3.65%+N
N= 96.35%
The frequency of carrier(Nn) in population would be:
Nn= 2*N*n
Nn= 2 * 3.65% * 96.35%
Nn= 0.0703
The chance that both of the parent is carrier would be: 0.07*0.07= 0.0049= 0.49%
