In order to find x, we first need to solve the ABC for side BC, then we can solve the right triangle from BC's length. The left triangle is a 45-45-90. And the sides are: [tex]y-y-y \sqrt{2} \\ so \: x \sqrt{2} \: = 6 \sqrt{2} \\ y(bc) = \frac{6 \sqrt{2}}{\sqrt{2} } = 6[/tex] for the right 30-60-90, the ratios are: [tex]x - x \sqrt{3} - 2x \\ so \: 2x = 6 \\ x = 3[/tex]
