f(x)=x^2+12x+26
Vertex form of f(x) = a(x-h)^2 +k
We change f(x) into vertex form using completing the square method
[tex] f(x)=x^2+12x+26 [/tex]
We take half of square of middle term
middle term is 12
Half of square of 12 is [tex] \frac{12}{2}=6 [/tex] then 6^2 = 36
Add and subtract 36 to complete the square
[tex] f(x)=(x^2+12x+36)+26-36 [/tex]
[tex] f(x)= (x+6)^2 +26 - 36
f(x)= (x+6)^2 -10 [/tex]
The vertex form [tex] f(x)= (x+6)^2 -10 [/tex]
