We are given
both triangles are similar
Let's assume side of bigger triangle is 'a'
side of smaller triangle is 'b'
so, a=54cm
b=18cm
now, we can find ratios
[tex] \frac{a}{b}= \frac{54}{18} [/tex]
[tex] \frac{a}{b}= 3 [/tex]
The area of the larger triangle is 603 cm²
so,
[tex] A_l=603 [/tex]
area of smaller triangle is As
we are given
both triangles are similar
so, we get
[tex] \frac{A_l}{A_s} =(\frac{a}{b}) ^2 [/tex]
now, we can plug values
and we get
[tex] \frac{603}{A_s} =(3) ^2 [/tex]
[tex] A_s=\frac{603}{3^2} [/tex]
[tex] A_s=67cm^2 [/tex]
so,
the area of smaller triangle is [tex] 67cm^2 [/tex]..........Answer
