xavierayala
contestada

the area of a rectangle is 54x^9y^8 square yards if the length of the rectangle is 6x^3y^4 yards what expression represents the width of the rectangle in yards

Respuesta :

We are given rectangle

[tex] Area=54x^9y^8 [/tex]

so, we have

[tex] A=54x^9y^8 [/tex]

[tex] length=6x^3y^4 [/tex]

so, we have

[tex] L=6x^3y^4 [/tex]

Let's assume

width of the rectangle in yards as W

we know that

[tex] A=L*W [/tex]

now, we can plug values

[tex] 54x^9y^8=(6x^3y^4)*W [/tex]

now, we can solve for W

[tex] W=\frac{54x^9y^8}{6x^3y^4} [/tex]

[tex] W=9x^6y^4 [/tex]

so, width of rectangle is [tex] 9x^6y^4 [/tex]............Answer

The expression that represents the width of the rectangle in yards is; W = 9(x^(6))y⁴

Area of a rectangle

The formula for area of a rectangle is;

A = length × width

We are given;

  • Area = 54x^(9) × y^(8) yd²
  • Length = 6x³y⁴ yd

Thus, width is;

W = A/L

W = (54x^(9) × y^(8))/(6x³y⁴)

Now, According to law of exponents, we know that; x¹¹/x² = x¹¹ ¯ ²

Thus,applying that same concept to our question gives;

W = (54/6) × (x^(9 - 3)) × y^(8 - 4)

W = 9(x^(6))y⁴

Read more on Area of rectangle at; https://brainly.com/question/13048427

Otras preguntas