Respuesta :
check the picture below.
[tex]\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in feet} \\\\ h(t) = -16t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\stackrel{29}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{6}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\\\ h(t)=-16t^2+29+6\implies \stackrel{h(t)}{0}=-16t^2+29+6 \\\\\\ 16t^2-29-6=0\implies (16t+3)(t-2)=0\implies t= \begin{cases} -\frac{3}{16}\\\\ \boxed{2} \end{cases}[/tex]
it cannot be a negative value, since it's seconds after the ball went up, so is not -3/16.
[tex]\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in feet} \\\\ h(t) = -16t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\stackrel{29}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{6}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\\\ h(t)=-16t^2+29+6\implies \stackrel{h(t)}{0}=-16t^2+29+6 \\\\\\ 16t^2-29-6=0\implies (16t+3)(t-2)=0\implies t= \begin{cases} -\frac{3}{16}\\\\ \boxed{2} \end{cases}[/tex]
it cannot be a negative value, since it's seconds after the ball went up, so is not -3/16.
The number of seconds which pass before the baseball hits the ground which is thrown into the air with an initial upward velocity of 29 ft/s is 2 seconds.
What is the equation of motion?
The equation of motion is the relation between the distance, velocity, acceleration and time of a moving body.
A baseball is thrown into the air with an initial upward velocity of 29 ft/s and an initial height of 6ft.
The formula which gives the ball’s height, h, in feet at time, t, in seconds is,
[tex]h(t) = -16t ^2 + 29t + 6[/tex]
When the ball hits the ground, the height of the baseball is zero. Thus,
[tex]h(t) = -16t ^2 + 29t + 6\\0 = -16t ^2 + 29t + 6\\16t ^2 - 29t - 6=0[/tex]
On solving this quadratic equation, we get the roots of it as 2 and -3/16. Taking positive root, the time taken is 2 seconds.
Thus, the number of seconds which pass before the baseball hits the ground which is thrown into the air with an initial upward velocity of 29 ft/s is 2 seconds.
Learn more about the equation of motion here;
https://brainly.com/question/13763238
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