Answer: The value of x = 7 and the value of y = 7√2.
Step-by-step explanation:
Since we have given that
Let ABC is a right angled triangle , right angle at B.
AB = 7
BC = x
AC = y
∠ACB = 45°
We need to find the value of x and y:
As we know the "Trigonometric ratio":
[tex]\tan 45^\circ=\frac{AB}{BC}=\frac{7}{x}\\\\1=\frac{7}{x}\\\\x=7[/tex]
Similarly,
[tex]\sin 45^\circ=\frac{AB}{AC}=\frac{7}{y}\\\\\frac{1}{\sqrt{2}}=\frac{7}{y}\\\\y=7\sqrt{2}[/tex]
Hence, the value of x = 7 and the value of y = 7√2.
