Chloroform (CHCl3), an important solvent, is produced by a reaction between methane and chlorine. CH4(g) + 3 Cl2(g) CHCl3(g) + 3 HCl(g) How many grams of CH4 is needed to produce 37.5 g CHCl3?
CH₄(g) + 3 Cl₂(g) → CHCl₃(g) + 3 HCl(g) From the equation we notice that 1 mole of methane produces 1 mole of chloroform: 16 g Methane → 119.38 g Chloroform ? g Methane → 37.5 g Chloroform by cross multiplication: = (16 * 37.5) / 119.38 = 5.0 g methane
