Respuesta :
The enlarged length is (3/2)*10 ft = 15 ft.
The enlarged width is (3/2)*4 ft = 6 ft.
The dimensions of the enlarged poster are ...
6 ft by 15 ft
The enlarged width is (3/2)*4 ft = 6 ft.
The dimensions of the enlarged poster are ...
6 ft by 15 ft
Answer:
The dimensions of the enlarged poster are [tex]6\ ft[/tex] by [tex]15\ ft[/tex]
Step-by-step explanation:
we know that
The scale factor is equal to the measure of the corresponding side of the enlarged poster divide by the the measure of the corresponding side of the original poster
Let
z-----> scale factor
x------> the measure of the corresponding side of the enlarged poster
y------> the measure of the corresponding side of the original poster
so
[tex]z=\frac{x}{y}[/tex]
In this problem we have
[tex]z=\frac{3}{2}=1.5[/tex]
Step 1
Find the length of the enlarged poster
[tex]x=zy[/tex]
we have
[tex]z=1.5[/tex]
[tex]y=10\ ft[/tex]
substitute
[tex]x=1.5(10)=15\ ft[/tex]
Step 2
Find the width of the enlarged poster
[tex]x=zy[/tex]
we have
[tex]z=1.5[/tex]
[tex]y=4\ ft[/tex]
substitute
[tex]x=1.5(4)=6\ ft[/tex]
therefore
the dimensions of the enlarged poster are [tex]6\ ft[/tex] by [tex]15\ ft[/tex]