We are given
[tex] x^2+4y^2=36 [/tex]
Since, this is equation of ellipse
so, firstly we will change it into standard equation of ellipse
[tex] \frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1 [/tex]
now, we can change our equation into this form
[tex] x^2+4y^2=36 [/tex]
we divide both sides by 36
we get
[tex] \frac{x^2}{36}+ \frac{4y^2}{36} =1 [/tex]
now, we can simplify it
[tex] \frac{x^2}{6^2}+ \frac{y^2}{3^2} =1 [/tex]
now, we can compare and find 'a' and 'b'
[tex] a=6, b=3 [/tex]
Since, shorter value is b
so, length of minor axis is 2b
length of minor axis is 2*3
The length of minor axis is 6...........Answer
