x - lb 7% fertilizer
y - lb 8% fertilizer
1) x+y = 400
2) 0.07x - lb nitrogen in x lb 7% fertilizer
0.08y - lb nitrogen in y lb 8% fertilizer
0.077*400=30.8 lb nitrogen in 400 lb 7.7% fertilizer
0.07x + 0.08y = 30.8
System of equation:
x+y = 400 /*(-0.08) -----> -0.08x-0.08y =-32
0.07x + 0.08y = 30.8
-0.08x-0.08y =-32
0.07x + 0.08y = 30.8 Add 2 equations.
-0.01x = -1.2
x=120 lb 7% fertilizer must be used