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A tank holds a 1.44-m thick layer of oil that floats on a 0.96-m thick layer of brine. both liquids are clear and do not intermix. point o is at the bottom of the tank, on a vertical axis. the indices of refraction of the oil and the brine are 1.40 and 1.52, respectively. a ray originating at o reaches the brine-oil interface at the critical angle. what is the distance of this point from the axis?

Respuesta :

IsrarAwan
The correct answer is: 2.3m

Explanation:

Since

sinθ  =  refraction-of-the-oil/refraction-of-the-brine =1.40/1.52 = 0.921
θ = [tex]sin^{-1}[/tex](0.921)
Hence
Critical angle = θ = 67.1°

tan(θ) = d/0.96
tan(67.1°) = d/0.96
Hence, 2.365 = d/0.96
The distance d = 2.365*0.96 = 2.27 = 2.3 m

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