A golf ball is chipped into the air from a small hill with an upward velocity of 50 ft/s. Its height h in feet after t seconds is given by the function . What is the maximum height in feet that the ball reaches? Round your answer to the nearest whole number.
From the model given: h(t)=-16t^2+50t+10 at the maximum height h'(t)=0 from the function: h'(t)=-32t+50 thus -32t+50=0 t=50/32 thus at maximum height: t=50/32~1.5625 hence, the maximum height will be: distance=speed*time distance=1.5625×50 =78.125 ft
