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Li wants to add these items to her suitcase: a hairdryer (1.25 lb), a hand-held video game (0.6 lb), an extra video game (0.25 lb), and a music player (0.4 lb). Using the inequality x ≤ 2.25, can she add all these items to the suitcase? If not, what could be left out to be closest to the maximum weight allowed? Explain.


Her suitcase already is 47.75 with a 50 lbs limit. There is an extra fee once you go past the limit

PLZ HELP!!

Respuesta :

26remirdakd

Answer:

add up all of the weights and see if it's less than 2.25 or not

1.25+0.6+0.25+0.4 = 2.5

2.5 is not less than 2.25, so she can't add all of the items

Step-by-step explanation:

\(^~^)/

MrRoyal

Inequalities are used to relate expressions of unequal values.

  • She cannot add all the items to the suitcase
  • She needs to remove the extra video game.

The items and their weights are:

[tex]\mathbf{Hairdryer = 1.25lb}[/tex]

[tex]\mathbf{Video\ Game = 0.6lb}[/tex]

[tex]\mathbf{Extra\ Video\ Game = 0.25lb}[/tex]

[tex]\mathbf{Music\ Player = 0.4lb}[/tex]

Add up the weights of the items

[tex]\mathbf{x = 1.25 + 0.6 + 0.25 + 0.4}[/tex]

[tex]\mathbf{x = 2.5}[/tex]

By comparison:

[tex]\mathbf{2.5 > 2.25}[/tex]

This means that:

She cannot add all the items to the suitcase

Subtract the weight of the items and the weight limit

[tex]\mathbf{2.5 - 2.25 = 0.25}[/tex]

This means that:

She needs to remove a weight of 0.25lb

The extra video game weighs 0.25 lb

Hence, she needs to remove the extra video game.

Read more about inequalities at:

https://brainly.com/question/20382422

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