the options given are as follows
a. Cl2
b. NO
c. NO2
d. SO2
e. C2H6
we can use the ideal gas law equation to find the number of moles of gas in the container
PV = nRT
where
P - pressure - 1.38 atm x 101 325 Pa/atm = 139 829 Pa
V - volume - 0.682 x 10⁻³ m³
n - number of moles
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature - 60 °C + 273 = 333 K
Substituting these values in the equation
139 829 Pa x 0.682 x 10⁻³ m³ = n x 8.314 Jmol⁻¹K⁻¹ x 333 K
n = 0.0344 mol
mass present - 1.58 g
molar mass = mass present / number of moles
therefore molar mass - 1.58 g / 0.0344 mol = 46 g/mol
the answer is NO₂
the molar mass of NO₂ is - 14 + (16x2) = 14 + 32 = 46
therefore unknown gas is NO₂
