A mixture contains 40 ounces of glycol and water and it is 10% glycol the mixture is to be strengthened to 25% by adding glycol how much glycol is in the original mixture
40 oz of 10% glycol contains 40*0.1=4 oz of glycol, and 40-4=36 oz. of water.
To make a 25% glycol using 36 oz of water will make a total volume of 36*(4/3)=48 oz. Volume of pure glycol to be added = 48-40=8 oz
Therefore 8 oz of pure glycol must be added to the mixture to make a 25% solution.
Algebraic solution: Let x = volume of pure glycol required in oz. then 0.10*40+1.00*x = 0.25*(40+x) expand 4.0+x=10+0.25x solve (1-0.25x)=10-4=6 x=6/0.75=8 oz Therefore 8 oz of pure glycol must be added to the mixture to make a 25% solution.
