Respuesta :
slope=(y2-y1)/(x2-x1)=(10-5)/(-4-(-1))=-5/3
Let equation be y=-(5/3)+b => 10=-(5/3)(-4)+b => b=10/3
So the real equation is y=-5/3+10/3 (and not y=x-2)
A. y=x-2 is not equivalent to y=-5/3+10/3
B. y=x+ is not an equation, so cannot be an equivalence
C. 3y = –5x + 10 divide by three => y=-(5/3)+10/3 both slope and y-intercept are equal, so equivalent to y=-5/3+10/3
D. 3x + 15y = 30 divide by 15 => (1/5)x+y = 2 slope and y-intercept are both not equal, so not equivalent to y=-5/3+10/3
E. 5x + 3y = 10 divide by 3 => (5/3)x + y = 10/3 slope and y-intercept are both equal, so equivalent to y=-5/3+10/3
Let equation be y=-(5/3)+b => 10=-(5/3)(-4)+b => b=10/3
So the real equation is y=-5/3+10/3 (and not y=x-2)
A. y=x-2 is not equivalent to y=-5/3+10/3
B. y=x+ is not an equation, so cannot be an equivalence
C. 3y = –5x + 10 divide by three => y=-(5/3)+10/3 both slope and y-intercept are equal, so equivalent to y=-5/3+10/3
D. 3x + 15y = 30 divide by 15 => (1/5)x+y = 2 slope and y-intercept are both not equal, so not equivalent to y=-5/3+10/3
E. 5x + 3y = 10 divide by 3 => (5/3)x + y = 10/3 slope and y-intercept are both equal, so equivalent to y=-5/3+10/3
Answer:
answers are
B, C, E
for edge2020
Step-by-step explanation:
B: y=-5/3x+10/3
C: 3y=-5x+10
E: 5x+3y=10