let's do trial and error. the first option is (3,0) so x is 3 and y is 0. since 0<3 it fits the first one. and now we need to check if -3+5is less than or equal to 0. as it is 2 this won't work.
we can rule out the last one because 4 is not less than 3. so we just need to check the 2 middle answers.
both have y as 1 and 1<3 so the first inequity holds.
now let's check for the second.
we have x values of 6 and 2 and we want to know which one will give us
[tex]1 \geqslant - x + 5[/tex]
when x is 6 we get -1 and -1 is less than 1 so that works!
when x is w we get 3 which is not less than one, so that won't work.
So we find the point (6,1) is a solution to the system of equations because these values cause.both inequalities to be true!
