A diner asked its customers, 'Did you cook dinner last night?' The results on the survey are shown in the table below:

Male Female
Cooked dinner 312 234
Did not cook dinner 146 454

What is the probability that one of the customers chosen from this survey was a female and did not cook dinner?

a. 0.51
b. 0.65
c. 0.76
d. 0.40

Question

26-04-2018
Mathematics

contestada

A diner asked its customers, 'Did you cook dinner last night?' The results on the survey are shown in the table below:

Male Female
Cooked dinner 312 234
Did not cook dinner 146 454

What is the probability that one of the customers chosen from this survey was a female and did not cook dinner?

a. 0.51
b. 0.65
c. 0.76
d. 0.40

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Аноним Аноним · Answer 1 · 2018-05-03T05:19:54+02:00

The answer to this question is 39.6160558, which rounds to .40 d. You can find this out by adding all of the males and females who did and didn't cook to get 1146 total people. You then have 454 females whi=o didn't cook out of 1146 total people. To solve you can make the fraction 454/1146 is equal to ___/100. You multiply 454 times 100 then divide by 1146 to get 39.6160558. Also, this is a percent and you need to find the decimal value so you need to divide the by 100 to get .40 as your rounded answer.

law4rena law4rena · Answer 2 · 2018-09-11T05:01:33+02:00

law4rena law4rena

11-09-2018

The answer is D.

First you find out how many individuals participated in the survey by added the categories

312 + 146 + 234 + 454 = 1146

The question asked the probability that one of the customers chosen from this survey was a female and did not cook dinner.

Well there are 454 females that did not cook dinner.

You simply divide 454 by 1146

454/1146 = .396160558464223 = .40

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