Respuesta :
Use the Pythagoras theorem:-
diagonal^2 = 5^2+5^2 = 50
diagonal = sqrt 50 = 7.1 inches to nearest tenth
diagonal^2 = 5^2+5^2 = 50
diagonal = sqrt 50 = 7.1 inches to nearest tenth
It is given that the plate is a square.
Therefore, let us represent the side of the square by the variable, "a".
Therefore, it is given to us that: [tex] a=5 [/tex] inches.
Now, we have to find the diagonal of the square. We know that the diagonal, [tex] d [/tex] of a square is given by the formula:
[tex] d=a\sqrt{2} [/tex]
Applying the above formula to our case we get the diagonal to be as:
[tex] d=5\sqrt{2}\approx7.07 [/tex] inches.
Therefore, the length of the diagonal to the nearest tenth of an inch is:
[tex] d=7.1 [/tex] inches.
