Respuesta :

gmany
[tex]\sec x=\dfrac{1}{\cos x}\\\\\cot x=\dfrac{\cos x}{\sin x}[/tex]


[tex]\sec^2x\cot^2x=\dfrac{1}{\cos^2x}\cdot\dfrac{\cos^2x}{\sin^2x}=\dfrac{\cos^2x}{\cos^2x\sin^2x}=\dfrac{1}{\sin^2x}[/tex]

Answer:

csc^2(x)

Step-by-step explanation:

https://socratic.org/questions/how-do-you-simplify-sec-2xcot-2x

I used this and got a 100 on my test.

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