The perimeter of an isosceles triangle is [tex]16+8\sqrt{2}[/tex].
Given
The hypotenuse of an isosceles right triangle is equal to [tex]8\sqrt{2}[/tex].
What is the perimeter of the isosceles triangle?
The perimeter of an isosceles triangle is the sum of all three sides. an isosceles triangle has 2 equal sides, the perimeter is twice the equal sides plus the different sides.
The other side of the isosceles triangle is;
[tex]\rm 2x=8\sqrt{2}\\\\x=8[/tex]
Therefore,
The perimeter of the isosceles right triangle is;
[tex]\rm Perimeter =2(x)+Other side\\\\Perimeter = 2(8)+8\sqrt{2}\\\\Perimeter = 16+8\sqrt{2}[/tex]
Hence, the perimeter of an isosceles triangle is [tex]16+8\sqrt{2}[/tex].
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