Respuesta :

Let... the smaller integer be x

Then, the larger integer is 2x+26(Two times.. =2x, 26 more... is =2x+26

Both added is 74

2x+26=74

2x=74−26

2x=48

x=24

Answer:

Let two integers be x and y.

Consider x > y

The sum of two integers is 74.

⇒ x+y = 74                      .....[1]

It is also given that: The larger is 26 more than twice the smaller

⇒x = 2y +26             ......[2]

Substitute equation [2] into [1] we have;

[tex]2y+26+y = 74[/tex]

Combine like terms;

[tex]3y+26= 74[/tex]

Subtract 26 from both sides we have;

3y = 48

Divide both sides by 3 we have;

y = 16

Substitute the value of y in [2] we have;

x = 2(16)+26 = 32+26

x = 58

Therefore, the two integers are 58 and 16

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