Respuesta :

PBCHEM
Answer : Option C) 1

Explanation : Using the formula for finding pH of strong acid,

pH = - [tex] log_{10} [/tex] [[tex] H^{+} [/tex]] = -[tex] log_{10} [/tex] [0.1]
= -[tex] log_{10} [/tex] [tex] 10^{-1} [/tex] = - (-1) = 1.

This calculation shows how to find the pH of any acid if the concentration is given.
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Answer:

C = 1

Explanation:

For a strong acid, equation of dissociation reaction;

HX(aq) + H2O(l) —> X- + H3O+

For a strong acid, the equilibrium reaction lies strongly to the right.

pH = -log10[H3O+] = -log10[0.1] = -(-1) = 1.

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