Respuesta :
a. Li before K, so Li is more active, and the reaction will not take place.
b. Mg is more active than Al, Mg is before Al in the activity series, so this reaction should go.
c. Pb before Cu, so Pb is more active, and the reaction will not take place.
d. Na before Na, so Ca is more active, and the reaction will not take placCa
b. Mg is more active than Al, Mg is before Al in the activity series, so this reaction should go.
c. Pb before Cu, so Pb is more active, and the reaction will not take place.
d. Na before Na, so Ca is more active, and the reaction will not take placCa
Answer: The correct options are a, b and d.
Explanation:
Single displacement reaction is a type of chemical reaction in which a more reactive metal displaces a less reactive metal from its reaction. Equation for this reaction follows:
[tex]A+BC\rightarrow AC+B[/tex]
Metal A is more reactive than Metal B.
For the given options:
Option a: This reaction is a type of single displacement reaction because potassium is more reactive than lithium.
[tex]LiCl+K\rightarrow KCl+Li[/tex]
Option b: This reaction is a type of single displacement reaction because Magnesium is more reactive than Aluminium.
[tex]2AlBr_3+3Mg\rightarrow 3MgBr_2+2Al[/tex]
Option c: This reaction will not yield any product because copper is less reactive than lead.
[tex]Pb(NO_3)_2+Cu\rightarrow \text{No reaction}[/tex]
Option d: This reaction is a type of single displacement reaction because Sodium is more reactive than Calcium.
[tex]CaCl_2+2Na\rightarrow 2NaCl+Ca[/tex]
Hence, the correct options are a, b and d.
