density of water = [tex]1000 kg/m^3[/tex]
velocity of flow = [tex]10 m/s[/tex]
radius of pipe = [tex]0.030 m[/tex]
Height of second floor = [tex]2 m[/tex]
Now we can use here Bernuoli's Equation to find the speed of water flow at second floor
[tex]P_1 + 1/2\rho v_1^2 + \rho g h_1= P_2 + 1/2 \rho v_2^2 + \rho g h_2[/tex]
[tex]P + 1/2 * 1000 * 10^2 + 1000* 9.8 * 0 = P + 1/2 * 1000 * v^2 + 1000*9.8*2[/tex]
[tex]v = 7.8 m/s[/tex]
Now in order to find the radius of pipe we can use equation of continuity
[tex]A_1 v_1 = A_2 v_2[/tex]
[tex]\pi *0.030^2 * 10 = \pi * r^2 * 7.8[/tex]
[tex]r = 0.034 m[/tex]
So radius of pipe at second floor is 0.034 meter
