an object moving with uniform acceleration has a velocity of 12.0 cm/s in the positive x direction when its x coordinate is 3.00 cm if its x coordinate 2.00 s later is -5.00cm what is its acceleration

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mathmate mathmate · Answer 1 · 2018-08-26T00:03:30+02:00

Given:

at time t=0, X0=X(0)=3.00 cm, v(0)=12 cm/s

at time t=2, x(2)=-5

Use kinematics equation:

X(t)=X(0)+v(0)*t+at^2/2

Substitute =>

X(t)=3+12t+at^2/2

At t=2, X(2)=-5 =>

-5=3+12(2)+a(2^2)/2 =>

acceleration = a =(-5-3-24)/2 = -16 cm/s^2

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hamzaahmeds hamzaahmeds · Answer 2 · 2021-09-04T17:10:27+02:00

This question can be solved using the equations of motion.

The acceleration of the object is - 16 cm/s².

We can use the second equation of motion to find the acceleration of the object.

[tex]\Delta s = v_it+\frac{1}{2}at^2[/tex]

where,

Δs = distance covered = change in position = - 5 cm - 3 cm = - 8 cm

[tex]v_i[/tex] = initial velocity = 12 cm/s

t = time = 2 s

a = acceleration = ?

Therefore,

[tex]-8\ cm = (12\ cm/s)(2\ s)+\frac{1}{2}a(2\ s)^2\\\\\frac{-32\ cm}{2\ s^2} = a\\\\[/tex]

a = - 16 cm/s² (negative sign shows deceleration)

The attached picture shows the equations of motion.

Learn more about equations of motion here:

https://brainly.com/question/9772550?referrer=searchResults