For this case we have that the point-slope form of a line is given by:
[tex](y-y_ {1}) = m (x-x_ {1})[/tex]
Where:
m: is the slope
[tex](x_ {1}, y_ {1})[/tex] are the coordinates of a point through which the line passes.
In this case we have to:
[tex]m = - \frac {1} {8}\\(x_ {1}, y_ {1}) = (-2, 1)[/tex]
Substituting we have:
[tex](y-1) = - \frac {1} {8} (x - (- 2))[/tex]
Simplifying: [tex]- * - = +[/tex]
[tex](y-1) = - \frac {1} {8} (x + 2)[/tex]
Thus, the point-slope equation form of the line is:[tex](y-1) = - \frac {1} {8} (x + 2)[/tex]
Answer:
[tex](y-1) = - \frac {1} {8} (x + 2)[/tex]
