The fish weigh is 56 ounces
To solve this problem, first step would be create two variables, x and y as follow:
x = fish weight
y = parakeet weight
Given:
From the problem above we can make two equations which are
x = 8y ⇒ first equation
x + y = 63 ⇒ second equation
The first step, we will substitute the first equation into the second equation to get the y variable:
x + y = 63
8y + y = 63
9y = 63
y = 7
then we substitute the y=7 into the second equation (either 1st or 2nd equation)
x + y = 63
x + 7 = 63
x = 56
So, jill's fish weigh is 56 ounces
Substitution method brainly.com/question/10852714
Substitution and elimination method in solving problem brainly.com/question/316466
Keywords: substitution, linear program
The weight of Jill’s fish is [tex]56{\text{ ounces}}[/tex] and the weight of parakeet is [tex]\boxed{{\mathbf{7 ounces}}}[/tex].
Further explanation:
Given:
It is given that the weight of Jill’s fish is 8 times as much as her parakeet. The total weight of fish and parakeet is .
Step by step explanation:
Step 1:
Consider [tex]x[/tex] as the weight of parakeet.
It is given that the weight of Jill’s fish is 8 times of the weight of parakeet.
Therefore, the weight of Jill’s fish can be expressed as [tex]8x[/tex].
Step 2:
The total weight of fish and parakeet is [tex]63{\text{ ounces}}[/tex].
Now make an equation for the total weight of fish and parakeet both as,
[tex]x + 8x = 63[/tex]
Now solve the equation [tex]x + 8x = 63[/tex] to obtain the value of [tex]x[/tex].
[tex]\begin{aligned}x + 8x &= 63 \\9x &= 63 \\\end{aligned}[/tex]
Now divide the resultant equation by 9 to obtain the value of [tex]x[/tex].
[tex]\begin{aligned}\frac{9}{9}x&= \frac{{63}}{9} \\x &= 7 \\\end{aligned}[/tex]
Therefore, the weight of parakeet is [tex]7{\text{ ounces}}[/tex].
Step 3:
Now find the weight of Jill’s fish that is [tex]8x[/tex] where [tex]x[/tex] is the weight of parakeet.
Now substitute the value of [tex]x = 7[/tex] in the expression [tex]8x[/tex] to obtain the weight of Jill’s fish as,
[tex]\begin{aligned}{\text{weight of fish}} &= 8x \\& = 8 \times 7 \\&= 56 \\\end{aligned}[/tex]
Therefore, the weight of Jill’s fish is [tex]56{\text{ ounces}}[/tex]and the weight of parakeet is [tex]7{\text{ ounces}}[/tex].
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Answer details:
Grade: Middle school
Subject: Mathematics
Chapter: Linear equation
Keywords: fish, parakeet, weight, ounces, equation, expression, addition, multiply, divide, number, total weight, Jill’s fish, real number, natural number
