Answer:
(1, 2)
Step-by-step explanation:
Just plug into the equation any number. It is preferred to always start with 0, and then make your way up consecutively. For this question, I'll only be writing the x values that are mentioned in the question.
Equation: [tex]y = \frac{2x + 1}{3}[/tex]
First value of x = 0
[tex]y = \frac{2(0) + 1}{3}[/tex] ⇒ Substitute it into the equation
[tex]y = \frac{0 + 1}{3}[/tex]
[tex]y = \frac{ 1}{3}[/tex]
∴ [tex](0, \frac{1}{3})[/tex]
Second value of x = 1
[tex]y = \frac{2(1) + 1}{3}[/tex] ⇒ Substitute it into the equation
[tex]y = \frac{2 + 1}{3}[/tex]
[tex]y = \frac{3}{3}[/tex]
[tex]y = 1[/tex]
∴ [tex](1, 1)[/tex]
Third value of x = 4
[tex]y = \frac{2(4) + 1}{3}\\[/tex] ⇒ Substitute it into the equation
[tex]y = \frac{8 + 1}{3}[/tex]
[tex]y = \frac{9}{3}[/tex]
[tex]y = 3[/tex]
∴ [tex](4, 3)[/tex]
When comparing our answers to the ones given in the question, everything matches except the first option; (1, 2).
Therefore, from the pairs of numbers given, (1, 2) is not a solution.
