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Triangle ABC has vertices A(0, 0), B(3, 3), C(6, 0). Write the equation of the line containing the altitude AR
A. y = -x
B. y = x
C. y = -x+1
D. y = x-1

Respuesta :

Answer:

(B)

Step-by-step explanation:

in order to find the equation of the line containing the altitude AR, first we find the slope of BC that is:

Slope of BC=[tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{0-3}{6-3}=-1[/tex]

Also, AR is perpendicular to BC, therefore slope of CD=[tex]-\frac{1}{slope of BC}=\frac{-1}{-1}=1[/tex]

Now, AR passes through point (0,0),using the point-slope form of the equation of a line, the equation of  AR is:

[tex]y-y_{1}=slope of AR(x-x_{1})[/tex]

[tex]y-0=(1)(x-0)[/tex]

[tex]y=x[/tex]

which is the required equation.

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